Question 203467
(ab+b^2) / (4ab^5) /(a+b) / (6a^2b^4)
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as  with  fractions,  invert  and  multiply,,,last  two  divisors
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[(ab+b^2) / (4ab^5)] * [ 6a^2b^4 / (a+b) ]
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factor
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[ (b)(a+b) / (4ab^5) ] * [  (6a^2b^4) / (a+b) ]
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simplify  by  cancelling  like  terms
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(6a)/4
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(3/2)a,,,,,(3a)/2
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check,,,Let  a=1,,,b=2,,,,both  original  and  answer = 3/2,,,ok