<PRE><B>Question 203481</B>
The first one lends itself to the substitution method
:
y= -3x+19
y= 2x - 1
Look at the 2nd equation, it should be apparent that we can
substitute (2x-1) for y in the 1st equation, then find x
2x - 1 = -3x + 19
2x + 3x = 19 + 1
5x = 20
x = {{{20/5}}}
x = 4
Use the 2nd equation to find y. Substitute 4 for x
y = 2(4) - 1
y = 8 - 1
y = 7
Check your solutions by substitution in the 1st equation
y = - 3x + 19
7 = -3(4) + 19
7 = -12 + 19; confirms our solutions
:
:
The 2nd equation lends itself to the elimination method
 x + 3y = 2
-x +  y = 1
-------------adding these eliminates x, find y
0x + 4y = 3
y = {{{3/4}}}
:
Find x using the 1st equation, substitute 3/4 of y
x + 3(3/4) = 2
x + 9/4 = 2
x = 2 - 9/4
x = -1/4
:
Check solution in the 2nd equation
-x + y = 1
-(-1/4) + (3/4) = 1
+1/4 + 3/4 = 1</PRE>