Question 28071
y=x-2 and {{{y=x^2-2}}}


Solving means where are they equal? How to do that? by putting them EQUAL! Sounds obvious, but that needs to be said, since you do not know how to solve this.


well, if y equal (x-2) and also y equal {{{x^2-2}}}, then surely {{{x-2 = x^2-2}}}?


{{{x-2 = x^2-2}}}
{{{-2 = x^2-x-2}}}
{{{0 = x^2-x}}}
just re-ordering... {{{x^2-x = 0}}}
x(x-1) = 0


so either x=0 OR x-1=0
--> x=0 OR x=1


and when x=0, y=-2
and when x=1, y=-1


(0, -2) and (1, -1) are the 2 answers (the 2 points) that satisfy BOTH equations.


Graphically, we have a quadratic, u-shape and a straight line. The  straight line cuts the u-shape twice and the coordinates i found are these two points.


the graph is...


{{{graph(300,300,-4,4,-6,6, x-2, x^2-2)}}}


jon.