Question 203358
5i^3/2(square root -4). 
:
{{{(5i^3)/(2sqrt(-4))}}}
:
i^3 = i^2 * i; i^2 = -1, therefore -1*i = -i
we have
{{{(-5i)/(2sqrt(-4))}}}
;
Extract Square root of neg 1 from the denominator
{{{(-5i)/(2i*sqrt(4))}}}
:
{{{(-5i)/(2i*2)}}}
:
{{{(-5i)/(4i)}}}
Cancel i
{{{(-5)/4)}}} = -1.25
:
You have to write it: -1.25 + 0i