Question 203260
A solution of salt and water contains 18 ounces of pure salt and 36 ounces of water. How many ounces of water must be added to obtain a 24% pure salt solution? 
.
Let x = amount of water to be added
then
"amount of salt" = 24% of "total volume"
18 = .24(18+36+x)
18 = .24(54+x)
18 = 12.96 + .24x
5.04 = .24x
21 ounces = x (amount of water to be added)