Question 203249
{{{3x^2 = 2x + 5}}}
{{{3x^2 - 2x -5 = 0}}}
{{{(3x-5)(x+1)=0}}}
so either (3x-5)=0 or (x+1)=0 , which means roots are 5/3 and -1

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Using quadratic equation
*[invoke quadratic "x", 3, -2, -5]