Question 28074
Factor:
{{{8t^3+27}}} This is a sum of two cubes and can be factored thus:
{{{A^3 +B^3 = (A+B)(A^2-AB+B^2)}}}

{{{8t^3+27 = (2t)^3+3^3}}} = {{{(2t+3)(4t^2-6t+9)}}} 

{{{27t^3+1 = (3t)^3+1^3}}} = {{{(3t+1)(9t^2-3t+1)}}}