Question 203148
Let a = the smaller number and b = the larger number, then...
1) a+b = 88  "The sum of two numbers is 88"
2) 3a = 2b+29  "Three times the smaller equals twice the larger plus 29"
Rewrite equation 1) as a = 88-b and substitute into equation 2).
3(88-b) = 2b+29  Simplify and solve for b.
264-3b = 2b+29  Add 3b to both sides.
264 = 5b+29  Subtract 29 from both sides.
235 =5b  FInally, divide both sides by 5.
47 = b and a = 88-47 = 41
The two numbers are:  41 and 47