<PRE><B>Question 203145</B>
One pump can fill a tank twice as fast as a second pump. If the pumps are used together, they fill the tank in 16 minutes. How long would it take each pump working alone to fill the tank?
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Faster pipe DATA:
time = x min/job ; rate = 1/x job/min
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Slower pipe DATA:
time = 2x min/job ; rate = 1/(2x) job/min
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Together DATA:
time = 16 min/job ; rate = 1/16 job/min
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Equation:
rate + rate = together rate
1/x + 1/(2x) = 1/16
Multiply thru by 16x to get:
16 + 8 = x
x = 24 minutes (time for the faster pipe to do the job)
2x = 48 minutes (time for the slower pipe to do the job)
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Cheers,
Stan H.</PRE>