Question 203068
Trains A and B are traveling in the same direction on parallel tracks.
 Train A is traveling at 60 mils per hour and train B is traveling at 70 mils per hour. 
Train A passes a station at 5:15 A. M. if train B passes station at 5:27 A.M,
 what time train b catch up train A? 
 
:
from the given information, we know that train B is 12 min (.2 hr) behind
 train A, when train A passes the station
:
The distance between the trains at this time: .2 * 70 = 14 mi
:
Let t = time required for train B to catch train a
:
write a distance equation: Dist = speed * time
:
Train A travel dist = Train b travel dist + 14 mi
70t = 60t + 14 
70t - 60t = 14
10t = 14
t = {{{14/10}}}
t = 1.4 hr or 1 hr 24 min
:
5:15 + 1:24 = 6:39 AM, B catches A
:
:
Check solution by finding the dist traveled by each train
70*1.4 = 98 mi
60*1.4 = 84 mi
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differ = 14 mi