Question 203090
 the sum of two numbers is 996. the difference of the larger and twice the smaller is 33. find the 2 numbers 
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Equations:
x + y = 996
x -2y = 33
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Subtract the 2nd Eq. from the 1st to get:
3y = 963
y = 321
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Substitute into x+y = 996 to solve for "x":
x + 321 = 996
x = 675
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Cheers,
Stan H.