Question 203062
It would help if you were to use paretheses to clarify the problem, eg:
((k^2+3k-10)/(36))*(3/(k^2-4)) I hope I've got this right!
{{{((k^2+3k-10)/36)*(3/(k^2-4))}}} Factor the first numerator and denominator and factor the second denominator.
{{{(cross((k-2))(k+5)/(cross(3)*12))*(cross(3)/(k+2)(cross(k-2)))}}} Cancel the common factors as shown to leave you with:
{{{highlight((k+5)/(12*(k+2)))}}} or {{{highlight_green((k+5)/(12k+24))}}}