Question 203012
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Solve the given equation for *[tex \Large y], that is put it into *[tex \Large y = mx + b] form.  Then determine the slope of the given line by inspection of the coefficient on *[tex \Large x].


Knowing the slope of the given line will tell you the slope of the perpendicular  line, because:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1 \perp L_2 \ \ \Leftrightarrow\ \ m_1 = -\frac{1}{m_2} \text{ and } m_1, m_2 \neq 0]


Since the two lines intersect on the *[tex \Large x]-axis, you can find the point of intersection by determining the *[tex \Large x]-intercept of the given equation.  Substitute 0 for *[tex \Large y] in the original equation and then do the arithmetic to solve for *[tex \Large x].  The *[tex \Large x]-intercept is a point of the form *[tex \Large (a,0)] where *[tex \Large a] is the value you just calculated.


With the slope of the desired line and the *[tex \Large x]-intercept point use the point-slope form to derived the desired equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y - 0 = m(x - a) ]


where *[tex \Large \left(a,0\right)] is the given point and *[tex \Large m] is the slope determined above.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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