Question 203015
<font face="Garamond" size="+2">


Solve the given equation for *[tex \Large y], that is put it into *[tex \Large y = mx + b] form.  Then determine the slope of the given line by inspection of the coefficient on *[tex \Large x].


Knowing the slope of the given line will tell you the slope of the parallel line, because:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1 \parallel L_2 \ \ \Leftrightarrow\ \ m_1 = m_2]


Now that you have the slope of the desired line, you can use that and the given point in the point-slope form to derived the desired equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y - y_1 = m(x - x_1) ]


where *[tex \Large \left(x_1,y_1\right)] is the given point and *[tex \Large m] is the slope determined above.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>