Question 202917
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Let *[tex \Large x] represent the original amount invested by each.  Since A gained *[tex \Large \frac{1}{5}], A now has *[tex \Large x + \frac{x}{5} =\frac{6x}{5}].  B lost $200, so he now has *[tex \Large x - 200], and two times that is what A has, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{6x}{5} = 2(x - 200)]


Solve for *[tex \Large x] 


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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