Question 202957
Note: we're not solving the equation, we're simply plugging in a value for "x" and evaluating.



{{{f(x)=2x^3-3x^2+x-21}}} Start with the given equation.



{{{f(1)=2(red(1))^3-3(red(1))^2+red(1)-21}}} Plug in {{{x=1}}}.



{{{f(1)=2(red(1))-3(1)^2+1-21}}} Cube {{{1}}} to get {{{1}}}.



{{{f(1)=2(1)-3(red(1))+1-21}}} Square {{{1}}} to get {{{1}}}.



{{{f(1)=red(2)-3(1)+1-21}}} Multiply {{{2}}} and {{{1}}} to get {{{2}}}.



{{{f(1)=2-red(3)+1-21}}} Multiply {{{-3}}} and {{{1}}} to get {{{-3}}}.



{{{f(1)=red(-21)}}} Combine like terms.



So the answer is {{{f(1)=-21}}}