Question 202938
Remember  log (a/b) =log(a) -log(b),,,,and  log(a*b) = log(a) + log(b),,,,,
and  log(a^b) = b*log(a)
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log(a) {x^4 / yz^2},,,,,
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log(a) x^4 - log(a)y -log(a)z^2
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4*log(a)x-log(a)y -2*log(a)z
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check,,Let  a=10,,,,x=1,,,y=2,,,z=3
original,,,log(10) {(1)^4 / (2)(3^2) } =  -1.255
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answer,,,4 * log(10)1 -log(10)2  -2*log(10) 3 = 0 - .3-2*.477= -1.255,,,,ok