Question 202909
<font face="Garamond" size="+2">


The perimeter of a rectangle is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P = 2l + 2w]


But if we let *[tex \Large w] represent the width, then *[tex \Large 6w] represents the width.  Therefore the perimeter is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P = 2(6w) + 2w = 14w]


Now all you need is the value of *[tex \Large w]


The area of a rectangle is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A = lw] and we know the area is 150,


so


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ lw = 6w\cdot w = 6w^2 = 150]


Solve for *[tex \Large w] and multiply by 14.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>