Question 28054
2x-4y=8
-3x+6y=5

SINCE 3X IS CARRYING A NEGATIVE SIGN 
  THEN SOLVE FOR X 1ST.
  
  X3  2X-4Y=8
  X2 -3X+6Y=5
MULTIPLY 3 BY THE 1ST ROLE AND MULTIPLY 2 BY THE SECOND ROLE.

  GIVES YOU: 6X-12Y=24
            -
            -6X+12Y=10
  GIVES YOU 12X=14
 DIVIDE BOTH SIDE BY 12
  12X/12=14/12
GIVES YOU X=7/6
PICK ONE OF THE EQUATION FRON THE QUETION BEING GIVEN AND SUBSTITUTE X WHICH IS 7/6
   2X-4Y=8
   2[7/6]-4Y=8
    7/3-4Y=8
  SUBTRACT 7/3 FROM BOTH SIDE
  7/3-7/3-4Y=8-7/3
         -4Y=17/3
    DIVIDE BOTH SIDE BY -4
       -4Y/-4=17/3 / -4
 THEREFORE Y=  - 17/12