Question 202837

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(8,3\right)]. So this means that {{{x[1]=8}}} and {{{y[1]=3}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-6,9\right)].  So this means that {{{x[2]=-6}}} and {{{y[2]=9}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(9-3)/(-6-8)}}} Plug in {{{y[2]=9}}}, {{{y[1]=3}}}, {{{x[2]=-6}}}, and {{{x[1]=8}}}



{{{m=(6)/(-6-8)}}} Subtract {{{3}}} from {{{9}}} to get {{{6}}}



{{{m=(6)/(-14)}}} Subtract {{{8}}} from {{{-6}}} to get {{{-14}}}



{{{m=-3/7}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(8,3\right)] and *[Tex \LARGE \left(-6,9\right)] is {{{m=-3/7}}}