Question 202831
With the variable in the argument of the log function we need to rewrite the equation in exponential form to "get at" the x.
{{{log(2, (2x+2)) = 4}}}
{{{2x + 2 = 2^4}}}
{{{2x + 2 = 16}}}
Now we have a very simple equation to solve.
Subtract 2 from both sides:
{{{2x = 14}}}
Divide both sides by 2:
{{{x = 7}}}