Question 202806
Start with the formula for the perimeter of a rectangle:
1) {{{P = 2(L+W)}}} where L = length and W = width.
2) {{{W = (1/4)L}}} "The width (W) is one fourth the length (L)." Multiply both sides by 4.
2a) {{{4W = L}}}  Into equation 1) Substitute {{{P = 190}}} and {{{L = 4W}}}
1a) {{{190 = 2(4W+W)}}} Divide both sides by 2.
1b) {{{95 = (5W)}}} Divide both sides by 5.
1c) {{{highlight(19 = W)}}} and..
2b) {{{L = 4W}}}
2c) {{{L = 4(19)}}}
2d) {{{highlight(L = 76)}}}
The length is 76m. and the width is 19m.
Check:
{{{P = 2(L+W)}}} Substitute {{{L = 76}}} and {{{W = 19}}}
{{{P = 2(76+19)}}} Evaluate.
{{{P = 2(95)}}}
{{{P=  190}}} OK!