Question 202739
{{{ x^2+bx+c }}} is not really an equation.<br>
But if you want to factor it you can use the quadratic formula to do this (even though the quadratic formula is meant to be used on equations).<br>
If we use the quadratic formula on your expression we get:
{{{x = (-b +- sqrt(b^2 - 4*1*c))/(2*(1))}}}
which simplifies to:
{{{x = (-b +- sqrt(b^2 - 4c))/2}}}
Taking out the "+-" shorthand we get:
{{{x = (-b + sqrt(b^2 - 4c))/2}}} or {{{x = (-b - sqrt(b^2 - 4c))/2}}}<br>
We can now use these to factor the original expression:
{{{x^2 + bx + c = (x - (-b + sqrt(b^2 - 4c))/2)(x - (-b - sqrt(b^2 - 4c))/2)}}}<br>
If you're curious (and brave) try multiplying this out. You'll find that it simplifies to {{{x^2 + bx + c}}}!