Question 202691
Let the 3 numbers be (n-2), n , (n+2)
then
Square of third number=(n+2)*((n+2)=n^2+4n+4
Square of second number=n^2
Subtracting we get...4n+4 =100
4n=100-4=96
n=96/4=24
Numbers are 22, 24 and 26.
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Verification
Square of third number=26*26=676
Square of Second number=24*24=576
Difference=100
OK