Question 202614
Since we are given two info: the slope (8/9) and one point (6,-3),
we use the slope intercept form of the line {{{y-y_1=m(x-x_1)}}}

Here, m=8/9 {{{x_1}}}=6 and {{{y_1=-3}}}
so,

y-(-3)=8/9(x-6) substitute
y+3=8/9(x-6)
9(y+3)=8(x-6) multiply both sides by 9
9y+27=8x-48
8x-9y-75=0 the general equation of the line

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