Question 27997
[6x^3y^2-51x^2y^2-9xy^2]/ [4x^4y+4x^3y+x^2y]
nr = [6x^3y^2-51x^2y^2-9xy^2]-----(1)
=3xy^2[2x^2-17x-3]
dr=[4x^4y+4x^3y+x^2y]
=x^2y(4x^2+4x+1)
=x^2y(2x+1)^2   ----(2)
Your arguments are right and you have proceeded quite mathematically!
Observing your requirements and the nr and dr after simplification as far as they went,the quantity -51 is the culprit and it should have been just -15
(may be that 1 that takes the unit's place should have been in the tenth place and  vice versa for 5, that  is 15 is inadvertantly entered as 51)
With -15 in the place  of -51, the problem is quite simple and comes under simplifiable category.
Given  [6x^3y^2-15x^2y^2-9xy^2]/ [4x^4y+4x^3y+x^2y] say
= 3xy^2[2x^2-5x-3]/x^2y(4x^2+4x+1)
=(3y/x)[(2x+1)(x-3)]/[(2x+1)(2x+1)]
(cancelling (xy) in the nr and in the dr 
and factorising the nr and dr)                     
=3y(x-3)/x(2x+1) (cancelling (2x+1))