Question 202463
I don't have a table of logarithms, but I have a calculator.
It won't help you looking up the answers in the table, but it will provide the answers.
these are all presumably to the base 10.
1) log 7.83 = .893761762

2) log .068 = -1.167491087

3) antilog 0.3814 = 2.40657832

4) antilog (8.3174 - 10) = antilog (-1.6826) = .020768255

antilog should be the inverse function of the log.
inverse function of the log is the exponent.
if y = log(x), then 10^y = x
example:
2 = log(100), then 10^2 = 100
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in number 3, you have:
log (x) = .3814 which implies that 10^.3814 = x which means that x = 2.40657832.
this happens to be true because 10^.3814 = 2.40657832.
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in number 4, you have:
log(x) = (8.3174 - 10 ) = (-1.6826) which implies that 10^(-1.6826) = .020768255.
this happens to be true because 10^(-1.6826) = .020768255.
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not sure if I got you the answers you wanted.
anti-log, however, is the inverse of the log, and it was explained as being the exponential form.
logs are defined as follows:
{{{log(b,x) = y}}} if and only if {{{b^y = x}}}
in your problems, the base was assumed to be 10 since it wasn't mentioned.  this is the standard way of expressing logs.  no base mentioned, base = 10.
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