Question 202465


{{{2x-9y=3}}} Start with the given equation.



{{{-9y=3-2x}}} Subtract {{{2x}}} from both sides.



{{{-9y=-2x+3}}} Rearrange the terms.



{{{y=(-2x+3)/(-9)}}} Divide both sides by {{{-9}}} to isolate y.



{{{y=((-2)/(-9))x+(3)/(-9)}}} Break up the fraction.



{{{y=(2/9)x-1/3}}} Reduce.



So the equation {{{y=(2/9)x-1/3}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=2/9}}} and the y-intercept is {{{b=-1/3}}} note: the y-intercept is the point *[Tex \LARGE \left(0,-\frac{1}{3}\right)]