Question 202392
<font face="Garamond" size="+2">


Use:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1 \perp L_2 \ \ \Leftrightarrow\ \ m_1 = -\frac{1}{m_2} \text{ and } m_1, m_2 \neq 0]


and the slope of the given line determined by inspection of the equation presented in slope-intercept form to determine the slope of the desired perpendicular.


Then use the point-slope form of the equation of a line with the slope determined above and the given point to derive an equation for the desired perpendicular.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y - y_1 = m(x - x_1) ]


where *[tex \Large m] is the slope derived in the first step and *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point.


Finally, rearrange the equation into Standard Form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ Ax + By = C]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>