Question 202214
[(17a^2b^3)/(15b^3c^2)] * [ (18b^4c^3) / (8a^2bc^2)]
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to  resolve,  look  at  numbers  only,  then  a's  only, then b's  only,  and  finally c's  only.
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remember common  bases  multiply  by  adding  exponents,  divide  by  subtracting.
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numbers, (17*18) / (15*8) = (17*6)/(5*8) = 2.55
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a"s,,,,2-2=0,,,or a^0=1
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b"s,,,,3+4-3-1,,or b^3
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c's,,,,,3-2-2,,,or c^(-1) = 1/c
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combining,,,,2.55 b^3 /c