Question 202342
we  presume  the  problem  is  ,,,1/x<=x^2-1
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by  inspection ,,,,
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if  x=0,,,1/x is  undefined
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if  x=1,,,,,1<=1-1,,,1<=0,,,not  true
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if  x=2,,,,1/2<=2^2-1,,,,,1/2<=3,,,ok
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appears  to  be  x>1
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to  math  calc
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1/x <=(x^2-1)
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mult  by  x
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1<=x^3 -x
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take  log's
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log1<=logx^3-logx
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0<=3logx-1logx
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0<=2logx
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0<=logx
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x>=1,,,,,checking x=1,,not  true  ,,,therefore  x>1
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