Question 202349
I think this is your problem:

{{{5b^2(4b^2-3b)}}}/{{{40b^3-30b^2}}}


There's probably a way to make that fraction look better but I've tried a few times and I haven't mastered it.  Clearly, I need a tutor for how to make math problems look good on this website.  


Anyway, if the above is your problem, here is what you do.....



Let's first focus on your denominator:


{{{40b^3-30b^2}}}   Is there a number or variable (or both) that is common to both?   How about 10b?  Do you see how 10b is in {{{40b^3}}} as well as {{{30b^2}}}?


SO let's factor out that 10b......


{{{40b^3-30b^2}}} = {{{10b(4b^2 - 3b)}}}



So now your new problem (with the revised denominator is)....


{{{5b^2(4b^2-3b)}}}/{{{10b(4b^2 - 3b)}}}




Now can you see that the {{{4b^2-3b)}}} in the numerator will factor out the {{{4b^2-3b)}}} in the denominator??


SO, now you have:


{{{5b^2/10b}}} and this can be reduced to


{{{1b^2/2b}}} and (you are STILL not done!) this can be reduced to


{{{1b/2}}}


I hope this helps you. :-)