Question 202340
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If you have the *[tex \Large y]-intercept and another point, you have two points.  Since the *[tex \Large y]-intercept is the value of *[tex \Large y] where the graph of the line intersects the *[tex \Large y]-axis, the *[tex \Large x]-coordinate of that point must be zero, hence one of your points is (0,-2) and the other is (-3,4).


Just use the formula for the slope:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ m = \frac{y_1 - y_2}{x_1 - x_2}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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