Question 202332
For the equation, (x+1/x-1) + (2/x)= (x/x+1), your first step is to eliminate your denominator. This can be done by looking for the least common multiple of x, (x-1), and (x+1), which happens to be x(x-1)(x+1). 

As such, you want to multiply all three parts of your equation by x(x-1)(x+1). This multiplication preserves the equality of the equation. Your result is x(x-1)(x+1)(x+1)/(x-1) + 2x(x-1)(x+1)/x= x^2(x-1)(x+1)/(x+1), which simplifies to x(x+1)^2 + 2(x-1)(x+1)= x^2(x-1). 

Simplifying the quadratic equation, you get x^3+2x^2+x +2x^2-2=x^3-x^2. Your new quadratic equation becomes 5x^2+x-2=0. *[invoke quadratic "x", 5, 1, -2 ].