Question 202331
Factor:
{{{10a^2-640}}} Notice that each term is a multiple of 10, so you can first factor 10.
{{{10(a^2-64)}}} Now the binomial (in the parentheses) is the difference of two squares. {{{(a)^2-(8)^2}}} and the difference of two squares can be factored thus:
{{{A^2-B^2 = (A+B)(A-B)}}}, so apply this concept to the binomial to complete the factoring of the given expression.
{{{highlight(10a^2-640 = 10(a+8)(a-8))}}}
To check the solution, you need only multiply the three factors to see that you will arrive at the given expression.
{{{10*(a+8)(a-8) = 10*(a^2-8a+8a-64)}}} which simplifies to:
{{{10(a^2-64) = 10a^2-640}}}