Question 202309
john and peter are 448 meters apart. they start walking towards each other at the same time. peter walks at a speed of 3 m/s and john at 4 m/s. 
1. after how many minutes will they meet?
Peter DATA:
Distance = x meters ; rate = 3 m/s ; time = x/3 seconds
---
John DATA:
Distance = 448-x meters ; rate = 4 m/s ; time = d/r = (448-x)/4 seconds
---
Equation:
Peter time = John time
(448-x)/4 = x/3
4x = 3(448-x)
4x = 3*448 - 3x
7x = 3*448
x = 192 (distance Peter walks)
---
Time required for them to meet:
time = x/3 = 192/3 = 64 seconds = 1 minute 4 seconds
========================================================

2. what distance will each have walked when they meet
John will walk 448-x = 448-192 = 256 meters
====================================================
Cheers,
Stan H.