Question 202104
1.Complete each exercise leaving imaginary answer in i form. 
3 squareroots of -24 
= 3sqrt(-24)
=3*2i*sqrt(6)
= 6sqrt(6)i
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2.Complete each exercise leaving imaginary answer in i form. 
(3 - i) + (1 - 2i) 
= 4 - 3i
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3.Complete each exercise leaving imaginary answer in i form. 
(7 + 3i) - (2 +3i)
= 5 
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4.Complete each exercise leaving imaginary answer in i form. 
The squareroot of -25 + the squareroot of -16 + the squareroot of -9
= sqrt(-25) + sqrt(-16) + sqrt(-9)
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= 5i + 4i + 3i
---
= 12i
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5.Complete each exercise leaving imaginary answer in i form. 
(5 -i)(5 +i)
= 5^2 - i^2
= 25 + 1
= 26
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6.Complete each exercise leaving imaginary answer in i form. 
(-3 - 5i)(-3 + 5i) 
= (-3)^2 - (5i)^2
= 9 + 25
= 34
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7.Complete each exercise leaving imaginary answer in i form. 
5-6i^11 
= 6 -6*(-i)
= 6 + 6i
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8.Complete each exercise leaving imaginary answer in i form. 
10(4-3i)
= 40 - 30i
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9.Complete each exercise leaving imaginary answer in i form. 
i^12 + 1 
= 1 + 1
= 2
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10.Complete each exercise leaving imaginary answer in i form. 
(5-2i^2)^2
= 25 - 20i^2 + (2i)^2
= 25 + 20 + 4
= 49
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11.Complete each exercise leaving imaginary answer in i form. 
6 / 2i
= [6/2i][2i/2i]
= 12i/-4
= -3i
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12.Complete each exercise leaving imaginary answer in i form.
 

(2 + the square root of -3) (2 - the squareroot of -3)
= 4 - -3
= 7
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___________________________ ___________________________ 
(2) (2) 
* It doesn't come out right when i submit it but, each equation is over 2. 

13.Complete each exercise leaving imaginary answer in i form. 

(4 + i)/(3-2i)
---
= [(4+i)(3-2i)]/[(3+2i)/(3+2i)]
---
= [(4+i)(3-2i)]/[5]
= [12+2 +3i-8i]/5
= [14-5i]/5
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Cheers,
Stan H.