Question 202105
I'm assuming that the equation is {{{(3x^2-2)/6=0}}} (it's very hard to read)



{{{(3x^2-2)/6=0}}} Start with the given equation.



{{{3x^2-2=6*0}}} Multiply both sides by 6.



{{{3x^2-2=0}}} Multiply.



{{{3x^2=0+2}}}Add {{{2}}} to both sides.



{{{3x^2=2}}} Combine like terms.



{{{x^2=(2)/(3)}}} Divide both sides by {{{3}}}.



{{{x=""+-sqrt(2/3)}}} Take the square root of both sides.



{{{x=sqrt(2/3)}}} or {{{x=-sqrt(2/3)}}} Break up the "plus/minus" to form two equations.



{{{x=sqrt(6)/3}}} or {{{x=-sqrt(6)/3}}}  Simplify the square root.



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Answer:



So the solutions are {{{x=(sqrt(6))/(3)}}} or {{{x=-(sqrt(6))/(3)}}}.