Question 201673
Expand:
{{{ln((e^(3y))/(x^2))}}} Apply the "quotient rule" for logarithms.{{{Log[b](M/N) = Log[b](M) - Log[b](N)}}}.
{{{ln(e^(3y))-ln(x^2)}}} Now apply the "power rule" for logarithms.{{{Log[b](M^p) = p*Log[b](M)}}}
{{{3y*ln(e)-2*ln(x)}}} Substitute {{{ln(e) = 1}}}
{{{highlight(3y-2*ln(x))}}}