Question 202050
Side length of smaller square: {{{s=x}}}


Area of smaller square: {{{A=x^2}}}




Side length of larger square: {{{s=7x}}}


Area of larger square: {{{A=(7x)^2=49x^2}}}




Now simply divide the area of the larger square into the area of the smaller square to find out how many smaller squares will fit in the larger square:


{{{(49x^2)/(x^2)=(49*cross(x^2))/(cross(x^2))=49}}}



So 49 smaller squares can fit into the larger square.