Question 202033

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(1,-4\right)] and *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(3,6\right)].



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(6--4)/(3-1)}}} Plug in {{{y[2]=6}}}, {{{y[1]=-4}}}, {{{x[2]=3}}}, and {{{x[1]=1}}}



{{{m=(10)/(3-1)}}} Subtract {{{-4}}} from {{{6}}} to get {{{10}}}



{{{m=(10)/(2)}}} Subtract {{{1}}} from {{{3}}} to get {{{2}}}



{{{m=5}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(1,-4\right)] and *[Tex \LARGE \left(3,6\right)] is {{{m=5}}}