Question 201979
{{{4/(x+2)-3/(3x+6)}}} Start with the given expression.



{{{4/(x+2)-3/(3(x+2))}}} Factor the second denominator



{{{(3*4)/(3(x+2))-3/(3(x+2))}}} Multiply the first fraction by {{{3/3}}}



{{{12/(3(x+2))-3/(3(x+2))}}} Multiply



{{{(12-3)/(3(x+2))}}} Subtract the fractions.



{{{(9)/(3(x+2))}}} Subtract



{{{(3*3)/(3(x+2))}}} Factor 9 to get 3*3



{{{(cross(3)*3)/(cross(3)(x+2))}}} Cancel out the common terms.



{{{3/(x+2)}}} Simplify



So {{{4/(x+2)-3/(3x+6)=3/(x+2)}}} where {{{x<>-2}}}