Question 201971


{{{(4/3)(2q+6)-(5q-6)/6-q/3=0}}} Start with the given equation.



{{{cross(6)^2(4/cross(3))(2q+6)-cross(6)((5q-6)/cross(6))-cross(6)^2(q/cross(3))=6*0}}} Multiply every term outside the parenthesis by the LCD 6 to clear out the fractions.



{{{2*4(2q+6)-(5q-6)-2q=6*0}}} Simplify



{{{8(2q+6)-(5q-6)-2q=0}}} Multiply



{{{16q+48-5q+6-2q=0}}} Distribute.



{{{9q+54=0}}} Combine like terms on the left side.



{{{9q=0-54}}} Subtract {{{54}}} from both sides.



{{{9q=-54}}} Combine like terms on the right side.



{{{q=(-54)/(9)}}} Divide both sides by {{{9}}} to isolate {{{q}}}.



{{{q=-6}}} Reduce.



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Answer:


So the solution is {{{q=-6}}}