Question 201897
The formula for the sum of the first "n" terms of any geometric sequence is {{{S=(a(r^n-1))/(r-1)}}}



{{{S=(a(r^n-1))/(r-1)}}} Start with the given formula



{{{S=(1(2^5-1))/(2-1)}}} Plug in {{{a=1}}}, {{{r=2}}}, and {{{n=5}}}



{{{S=(1(32-1))/(2-1)}}} Raise 2 to the 5th power to get 32



{{{S=(1(31))/(1)}}} Subtract



{{{S=(31)/(1)}}} Multiply



{{{S=31}}} Divide



So the sum of the first five terms is 31 which means that the answer is C)