Question 201841
The previous solution is dead on in saying that the only number that "a" is NOT divisible is 4. Here's another way to look at it:


Recall that {{{a=4b}}}, means that "a" is divisible by 4 (ie "a" is a multiple of 4). However, once we add 26 on, we get {{{a=4b+26}}} which can be rewritten as {{{a=4b+24+2}}} and {{{a=4(b+6)+2}}} 



Now let p=b+6 ("p" is automatically an integer since "b" is). So we then get: {{{a=4p+2}}} which tells us that for ANY value of "p", {{{a/p}}} will result in a remainder of 2. This means that "a" is NOT divisible by 4 (since a non-zero remainder results every time).


So the answer is once again B) 4