Question 201820
(1) y+4x = x^2,,,,,,,y = x^2 -4x
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(2) y+x^2 +8 =6x,,,,,y = -x^2 +6x -8
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Set (1) =(2)
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x^2 -4x = -x^2 +6x -8
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2x^2 -10x +8 =0
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2(x^2 -5x +4) =0
(x-4)(x-1)=0
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x= 4, 1
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in(1) y+4(4) = (4)^2,,,,y=0,,,,,(4,0)
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y+4(1) = (1)^2,,,,y=-3,,,,,,,,,,,(1,-3)
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check,,,(1) 0+16=16,,,ok,,,,,,-3 +4 = 1,,,,,ok
(2) 0+16 +8 =24,,,,,ok,,,,,, -3 + 1 +8 =6,,,,ok,,,,,,