Question 201744
A retailer spent $48 to purchase a number of special mugs. Two of them were broken in the store, but by selling each of the remaining mugs for $3 above the original cost per mug, she made a total profit of $22. Need to solve for the number of mugs originally purchased? Denoted by n.
:
Price paid for each mug = {{{48/n}}}
:
No. of mugs sold = (n-2)
:
Selling price = {{{48/n}}} + 3
;
Total revenue = 48 + 22 = $70:
:
#sold * Price sold = total revenue
(n-2) * [{{{48/n}}} + 3] = 70
FOIL
48 + 3n - 96/n - 6 = 70
3n - 96/n + 42 - 70 = 0
3n - 96/n - 28 = 0
Multiply equation by n, forming a quadratic equation:
3n^2 - 28n - 96 = 0
Factor
(3n +8)(n-12) = 0
Positive solution
n = 12 mugs originally bought
:
Check
Cost: 48/12 = $4
Sold: 10 * 7 = $70 (cost + profit)