Question 201668
IF ONE ROOT OF THE POLYNOMIAL 
5x^2+13x+k
IS THE RECIPROCAL OF THE OTHER,THEN WHAT IS THE VALUE OF K
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Use the quadratic eqn to get the 2 roots.
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(-13 + sqrt(169-20k))/10 = 10/(-13 - sqrt(169-20k))
(-13 + sqrt(169-20k))*(-13 - sqrt(169-20k)) = 100
169 - (169-20k) = 100
20k = 100
k = 5
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To check:
*[invoke solve_quadratic_equation 5,13,5]