Question 201659
<font face="Garamond" size="+2">


So far, so good.  You multiplied each of the fractions on the left by *[tex \Large \frac{12}{12}], so now you have to multiply the right side by the same thing.  That is: *[tex \Large \frac{12}{12}\cdot\frac{1}{6} = \frac{2}{12}], so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{4}{12b}-\frac{9}{12b}\ >\ \frac{2}{12}]


Now multiply both sides by *[tex \Large 12b]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4 - 9\ >\ 2b \ \ \Rightarrow\ \ 2b\ <\ -5 \ \ \Rightarrow\ \ b\ <\ -\frac{5}{2}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>