Question 201652
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Rearrange both of your equations until they are in slope-intercept form, namely:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y = mx + b]


Then compare the coefficients on *[tex \Large x] (the *[tex \Large m] in *[tex \Large y = mx + b]).


If they are equal, the two lines are parallel.


If they are negative reciprocals, that is if *[tex \Large m_1 = -\frac{1}{m_2}], then the two lines are perpendicular.


Otherwise, they are neither.


These are the rules:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1 \parallel L_2 \ \ \Leftrightarrow\ \ m_1 = m_2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1 \perp L_2 \ \ \Leftrightarrow\ \ m_1 = -\frac{1}{m_2} \text{ and } m_1, m_2 \neq 0]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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